Safe current carrying capacity of copper wire is calculated by:

Safe loading capacity 2.5 mm2 copper power cord --28A.

Safe loading capacity 4 mm2 copper power cord --35A.

Safe loading capacity 6 mm2 copper power cord --48A.

10 mm2 safe carrying capacity of copper power cord --65A.

Safe loading capacity 16 mm2 copper power cord --91A.

Safe loading capacity 25 mm2 copper power cord --120A.

If aluminum wire, copper wire diameter of 1.5-2 times to take. If the current is less than the copper wire 28A, 10A per square millimeter to ...

Calculated cross-sectional area of the wire carrying capacity

First, the safe current carrying capacity ships carrying capacity of copper wire conductors is based on the allowed maximum conductor temperature, cooling conditions, laying conditions determined. Safe carrying capacity of copper wire is generally 5 ~ 8A / mm2, aluminum conductors carrying capacity of the safety of 3 ~ 5A / mm2. General Security carrying capacity of copper wire is 5 ~ 8A / mm2, aluminum conductors carrying capacity of the safety of 3 ~ 5A / mm2.

Such as: 2.5 mm2 BVV safe recommended copper wire carrying capacity 2.5 × 8A / mm2 = 20A 4 mm2 BVV recommended safe carrying capacity of copper wire 4 × 8A / mm2 = 32A

Second, the calculation of copper wire cross-sectional area of the use of copper wire recommended safe loading capacity of 5 ~ 8A / mm2, calculated selected copper wire cross-sectional area S of the upper and lower range: S = =0.125 I ~ 0.2 I (mm2)

S ----- copper conductor cross-sectional area (mm2) I ----- load current (A)

Third, the general load power calculation (can also be used appliances, such as lighting, refrigerators, etc.) are divided into two types, one type resistive load An inductive load. For resistive load formula: P = UI formula for fluorescent lamp load: P = UIcosф, where fluorescent load power factor cosф = 0.5. Different inductive load power factor is different, unified computing household appliances when the power factor to take cosф 0.8. That is, if all household appliances plus a total power of 6,000 watts, the maximum current is I = P / Ucosф = 6000/220 * 0.8 = 34 (A), however, under normal circumstances, home appliances can not be used simultaneously so plus a common factor, the common factor is generally 0.5. Therefore, the above calculation should be rewritten as I = P * Public coefficient /Ucosф=6000*0.5/220*0.8=17(A) In other words, the total current value of the family 17A. The total gate can not use the air switch 16A, 17A should be greater than the.

Common wire size 1 / 1.5 square (lighting) switch after the home improvement overall, 2.5 square (ordinary socket), 4, or 6 square squares (large air-conditioning and electrical appliances line)